tentukan perangkatan bilangan bulat
1)14²=
2)(-21)²=
3) (-11)²=
4)2³x2pangkat4=
5) (3pangkat4)²=
tolong di jawab pakai jalannya ya ![]()
1)14²=
2)(-21)²=
3) (-11)²=
4)2³x2pangkat4=
5) (3pangkat4)²=
tolong di jawab pakai jalannya ya
Jawaban:
1). 14² = 14 × 14 = 196
2). (-21)² = (-21) × (-21) = 441
3). (-11)² = (-11) × (-11) = 121
4). 2³ × 2⁴ = 2⁷ = 128
5). (3⁴)² = (81)² = 81 × 81 = 6561
Jawaban:
[tex]1) {14}^{2} = 14 \times 14 = 196[/tex]
[tex]2) \: { - 21}^{2} = - 21 \times - 21 = 441[/tex]
[tex]3) { - 11}^{2} = - 11 \times - 11 = 121[/tex]
[tex] 4) \: \: {2}^{3} \times {2}^{4} = {2}^{3 + 4} = {2}^{7} = (2 \times 2 \times 2) \times (2 \times 2 \times 2) \times 2 = 8 \times 8 \times 2 = 64 \times 2 = 128[/tex]
[tex]5) \: ({3}^{4}) {}^{2} = {3}^{4 \times 2} = {3}^{8} = (3 \times 3 \times 3 \times 3) \times (3 \times 3 \times 3 \times 3) = 81 \times 81 = 6.561[/tex]
semoga membantu :)
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